Difference between revisions of "Socket code in levels of complexity"
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− | Complexity 2, we can add logging<br> | + | '''Complexity 2''', we can add logging<br> |
<source lang="python"> | <source lang="python"> | ||
− | #!/usr/bin/python3 | + | #!/usr/bin/python3 |
import socket | import socket |
Latest revision as of 15:34, 20 January 2022
Complexity 1, very simple. Connect using "telnet localhost 9988", send a few characters and then press <enter>
The characters are echoed back and the connection is closed
#!/usr/bin/python3 import socket import sys s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.bind(("localhost", 9988)) s.listen(1) while True: conn, addr = s.accept() data = conn.recv(1024) conn.sendall(data) conn.close()
Complexity 2, we can add logging
#!/usr/bin/python3 import socket import logging import sys s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) logging.basicConfig(format='%(levelname)s - %(asctime)s: %(message)s',datefmt='%H:%M:%S', level=logging.DEBUG) s.bind(("localhost", 9988)) s.listen(1) while True: conn, addr = s.accept() data = conn.recv(1024) #print(data) logging.info(data.decode("utf-8")) conn.sendall(data) conn.close()